To solve this equation, we can apply the properties of logarithms:
Given log3(2x-1) = 2 - log3(x-4), we can rewrite this as:
3^(2 - log3(x-4)) = 2x - 1
3^2 / (x-4) = 2x - 1
9 / (x-4) = 2x - 1
9 = (2x - 1)(x - 4)
9 = 2x^2 - 9x + 4
2x^2 - 9x - 5 = 0
(2x + 1)(x - 5) = 0
2x + 1 = 0 or x - 5 = 0
2x = -1 or x = 5
x = -1/2 or x = 5
Therefore, the solutions to the equation log3(2x-1) = 2 - log3(x-4) are x = -1/2 or x = 5.
To solve this equation, we can apply the properties of logarithms:
Use the property loga(b) = c is equivalent to a^c = b.Given log3(2x-1) = 2 - log3(x-4), we can rewrite this as:
3^(2 - log3(x-4)) = 2x - 1
Use the property loga(b) - loga(c) = loga(b/c):3^2 / (x-4) = 2x - 1
9 / (x-4) = 2x - 1
Multiply both sides by (x-4) to get rid of the denominator:9 = (2x - 1)(x - 4)
Expand and simplify:9 = 2x^2 - 9x + 4
2x^2 - 9x - 5 = 0
Factor the quadratic equation:(2x + 1)(x - 5) = 0
Set each factor equal to zero:2x + 1 = 0 or x - 5 = 0
Solve for x:2x = -1 or x = 5
x = -1/2 or x = 5
Therefore, the solutions to the equation log3(2x-1) = 2 - log3(x-4) are x = -1/2 or x = 5.