To subtract mixed numbers, we first convert them to improper fractions.
For [tex]5 \frac{7}{8} [/tex]:[tex]5 \frac{7}{8} = \frac{(5 \times 8) + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8}[/tex]
For [tex]3 \frac{5}{6} [/tex]:[tex]3 \frac{5}{6} = \frac{(3 \times 6) + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6}[/tex]
So now the expression becomes:[tex]\frac{47}{8} - \frac{23}{6}[/tex]
To subtract fractions, we need a common denominator, which in this case is 24:
[tex]\frac{47 \times 3}{8 \times 3} - \frac{23 \times 4}{6 \times 4}[/tex][tex]= \frac{141}{24} - \frac{92}{24}[/tex][tex]= \frac{141 - 92}{24}[/tex][tex]= \frac{49}{24}[/tex]
Therefore, [tex]5 \frac{7}{8} - 3 \frac{5}{6} = 2 \frac{1}{24}[/tex]
To subtract mixed numbers, we first convert them to improper fractions.
For [tex]5 \frac{7}{8} [/tex]:
[tex]5 \frac{7}{8} = \frac{(5 \times 8) + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8}[/tex]
For [tex]3 \frac{5}{6} [/tex]:
[tex]3 \frac{5}{6} = \frac{(3 \times 6) + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6}[/tex]
So now the expression becomes:
[tex]\frac{47}{8} - \frac{23}{6}[/tex]
To subtract fractions, we need a common denominator, which in this case is 24:
[tex]\frac{47 \times 3}{8 \times 3} - \frac{23 \times 4}{6 \times 4}[/tex]
[tex]= \frac{141}{24} - \frac{92}{24}[/tex]
[tex]= \frac{141 - 92}{24}[/tex]
[tex]= \frac{49}{24}[/tex]
Therefore, [tex]5 \frac{7}{8} - 3 \frac{5}{6} = 2 \frac{1}{24}[/tex]