= sin(π/3 + α) + (1/2)sinα
Expanding sin(π/3 + α) using the sum and difference formula for sine, we get:
= sin(π/3)cosα + cos(π/3)sinα + (1/2)sinα
Since sin(π/3) = √3/2 and cos(π/3) = 1/2, we can substitute these values into the equation:
= (√3/2)cosα + (1/2)sinα + (1/2)sinα
= (√3/2)cosα + sinα
Therefore, the simplified expression is:
(√3/2)cosα + sinα + (1/2)sinα
= sin(π/3 + α) + (1/2)sinα
Expanding sin(π/3 + α) using the sum and difference formula for sine, we get:
= sin(π/3)cosα + cos(π/3)sinα + (1/2)sinα
Since sin(π/3) = √3/2 and cos(π/3) = 1/2, we can substitute these values into the equation:
= (√3/2)cosα + (1/2)sinα + (1/2)sinα
= (√3/2)cosα + sinα
Therefore, the simplified expression is:
(√3/2)cosα + sinα + (1/2)sinα