а)Подставляем значение а=2/3:1/5(10*2/3-6)-(5,2-2/3) =1/5(20/3-6)- (5,2-2/3) =1/5(20/3-18/3)- (5,2-2/3) =1/5(2/3)- (5,2-2/3) =2/15 - (5,2-2/3) =2/15 - (52/10-2/3) =2/15 - (26/5-2/3) =2/15 - (156/15-10/15) =2/15 - 146/15 =-144/15 = -32.
б)Подставляем значения m=6/41, n=0,1:35(0,86/41-2/70,1)-1/6(12,60,1+46/41) =35(4,8/41-0,2/7)- 1/6(1,26+24/41) =35(4,8/41-0,2/7)- 1/6(1,2641/41+24/41) =35(4,8/41-0,2/7)- 1/6(51,66/41) =35(4,8/41-0,241/41)- 1/6(51,66/41) =35(4,8/41-8,2/41)- 1/6(51,66/41) =35(-3,4/41)- 1/6(51,66/41) =
а)
Подставляем значение а=2/3:
1/5(10*2/3-6)-(5,2-2/3) =
1/5(20/3-6)- (5,2-2/3) =
1/5(20/3-18/3)- (5,2-2/3) =
1/5(2/3)- (5,2-2/3) =
2/15 - (5,2-2/3) =
2/15 - (52/10-2/3) =
2/15 - (26/5-2/3) =
2/15 - (156/15-10/15) =
2/15 - 146/15 =
-144/15 = -32.
б)
119/41 - 1/6*51,66/41=119/41 - 51,66/246=119/41 -2091,96/246=Подставляем значения m=6/41, n=0,1:
35(0,86/41-2/70,1)-1/6(12,60,1+46/41) =
35(4,8/41-0,2/7)- 1/6(1,26+24/41) =
35(4,8/41-0,2/7)- 1/6(1,2641/41+24/41) =
35(4,8/41-0,2/7)- 1/6(51,66/41) =
35(4,8/41-0,241/41)- 1/6(51,66/41) =
35(4,8/41-8,2/41)- 1/6(51,66/41) =
35(-3,4/41)- 1/6(51,66/41) =
-119/41 - 2091,96/246=
-119/41 - 8,5=
-69,793 неполный ответ.