Log0.5(log2(log1/3 (1/x))) >0

Предыдущий
вопрос Следующий
вопрос

To solve this inequality, we need to first simplify the expression inside the logarithms:

log1/3 (1/x) = log(1/x)^(1/3) = 1/3 log(1/x) = -1/3 log(x)

Now we can substitute this back into the original inequality:

log0.5(log2(-1/3 * log(x))) > 0

Since logarithms are only defined for positive arguments, we must have -1/3 * log(x) > 0, which simplifies to log(x) < 0. Multiplying both sides by -1, we get log(x) > 0, which means x > 1.

Therefore, the solution to the inequality log0.5(log2(-1/3 * log(x))) > 0 is x > 1.