Given that sinα = 3/5 and α is greater than π/2, we can find the values of sin^2α, cos^2α, and tan^2α by using the trigonometric identities and relationships.
Since sinα = 3/5, we can use the Pythagorean identity to find cosα:
cos^2α = 1 - sin^2cos^2α = 1 - (3/5)^cos^2α = 1 - 9/2cos^2α = 16/2cosα = √(16/25cosα = 4/5
Now, we can find sin^2α and cos^2α:
sin^2α = (3/5)^sin^2α = 9/25
cos^2α = (4/5)^cos^2α = 16/25
Lastly, we can find tan^2α:
tanα = sinα/costanα = (3/5) / (4/5tanα = 3/tan^2α = (3/4)^tan^2α = 9/16
Therefore, sin^2α = 9/25, cos^2α = 16/25, and tan^2α = 9/16.
Given that sinα = 3/5 and α is greater than π/2, we can find the values of sin^2α, cos^2α, and tan^2α by using the trigonometric identities and relationships.
Since sinα = 3/5, we can use the Pythagorean identity to find cosα:
cos^2α = 1 - sin^2
cos^2α = 1 - (3/5)^
cos^2α = 1 - 9/2
cos^2α = 16/2
cosα = √(16/25
cosα = 4/5
Now, we can find sin^2α and cos^2α:
sin^2α = (3/5)^
sin^2α = 9/25
cos^2α = (4/5)^
cos^2α = 16/25
Lastly, we can find tan^2α:
tanα = sinα/cos
tanα = (3/5) / (4/5
tanα = 3/
tan^2α = (3/4)^
tan^2α = 9/16
Therefore, sin^2α = 9/25, cos^2α = 16/25, and tan^2α = 9/16.