Lgx×lg(0,001x)=lg0.01

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To solve this equation, we can first simplify it by using the properties of logarithms:

lgx + lg(0.001x) = lg0.01

lg(x * 0.001x) = lg0.01

lg(0.001x^2) = lg0.01

Now, we can remove the logarithm by using 10 as the base:

0.001x^2 = 0.01

Now, we can solve for x:

0.001x^2 = 0.01

x^2 = 0.01 / 0.001

x^2 = 10

x = √10

Therefore, the solution to the equation lgx + lg(0.001x) = lg0.01 is x = √10.