To solve this equation, we can use the trigonometric identity: sin(a)sin(b) = (1/2)[cos(a-b) - cos(a+b)].
Applying this identity to the given equation, we get:
sin(x)sin(60-x) = (1/2)[cos(x-(60-x)) - cos(x+(60-x))]sin(x)sin(60-x) = (1/2)[cos(2x-60) - cos(120)]
Next, we use the double angle formula for cosine: cos(2x) = 1 - 2sin^2(x). Substituting this into the equation, we get:
sin(x)[1 - 2sin^2(x)] = (1/2)[1 - 2sin^2(x) - cos(120)]
Expanding and simplifying the equation gives:
sin(x) - 2sin^3(x) = (1/2)[1 - 2sin^2(x) + cos(120)]
Since cos(120) = -1/2, the equation becomes:
sin(x) - 2sin^3(x) = (1/2)[1 - 2sin^2(x) - 1/2]
Simplifying further, we get:
sin(x) - 2sin^3(x) = 2 - 4sin^2(x) - 1sin(x) - 2sin^3(x) = 1 - 4sin^2(x)
Rearranging terms gives:
2sin^3(x) - 4sin^2(x) + sin(x) - 1 = 0
By factoring out sin(x) - 1, we get:
(sin(x) - 1)(2sin^2(x) + 2sin(x) + 1) = 0
This equation has one solution: sin(x) = 1.
Therefore, the solution to the given equation is sin(x) = 1.
To solve this equation, we can use the trigonometric identity: sin(a)sin(b) = (1/2)[cos(a-b) - cos(a+b)].
Applying this identity to the given equation, we get:
sin(x)sin(60-x) = (1/2)[cos(x-(60-x)) - cos(x+(60-x))]
sin(x)sin(60-x) = (1/2)[cos(2x-60) - cos(120)]
Next, we use the double angle formula for cosine: cos(2x) = 1 - 2sin^2(x). Substituting this into the equation, we get:
sin(x)[1 - 2sin^2(x)] = (1/2)[1 - 2sin^2(x) - cos(120)]
Expanding and simplifying the equation gives:
sin(x) - 2sin^3(x) = (1/2)[1 - 2sin^2(x) + cos(120)]
Since cos(120) = -1/2, the equation becomes:
sin(x) - 2sin^3(x) = (1/2)[1 - 2sin^2(x) - 1/2]
Simplifying further, we get:
sin(x) - 2sin^3(x) = 2 - 4sin^2(x) - 1
sin(x) - 2sin^3(x) = 1 - 4sin^2(x)
Rearranging terms gives:
2sin^3(x) - 4sin^2(x) + sin(x) - 1 = 0
By factoring out sin(x) - 1, we get:
(sin(x) - 1)(2sin^2(x) + 2sin(x) + 1) = 0
This equation has one solution: sin(x) = 1.
Therefore, the solution to the given equation is sin(x) = 1.