(a-b)(x+y) равно (a-x)(b-y) равно (x+8)(y-1) равно (b-3)(a-2) равно $_$ (a-b)(x+y)
(a-x)(b-y)
(x+8)(y-1)
(b-3)(a-2)
For

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вопрос

the given expression to be equal, the factors must be interchangeable. This means that we can rearrange the factors in any way and the result will still be the same.

Therefore, we have:

(a - b)(x + y) = (a - x)(b - y) = (x + 8)(y - 1) = (b - 3)(a - 2) = $$_$

This means that all these expressions are equal to each other and can be interchanged without changing the value of the expression.