An object of mass 50 g just floats in a liquid of density 2.5 g/ml. When the object is placed in a
liquid of density 2.0 g/ml, it sinks to the bottom of the container. What is the force that the object
exerts on the bottom of the container?
the solids density is
[g = 10 m/s2 = 10 N/kg]
Can someone please write step by step, i would appreciate

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Sure, I'd be happy to help. Here's the step-by-step solution:

The weight of the object is equal to the force of gravity acting on it. The weight of the object in air can be calculated using the formula:
Weight = mass x acceleration due to gravity
Weight = 50 g x 10 m/s^2
Weight = 500 g*m/s^2

To determine if the object will float or sink in a liquid, we compare the density of the object to the density of the liquid. If the density of the object is greater than the density of the liquid, the object will sink.

In the first given liquid with a density of 2.5 g/ml, the object is floating. This means that the density of the object must be less than 2.5 g/ml.

In the second given liquid with a density of 2.0 g/ml, the object sinks. This means that the density of the object must be greater than 2.0 g/ml.

Since the object sinks in the liquid with a density of 2.0 g/ml, it must be more dense than 2.0 g/ml. To find the exact density of the object, we use the formula for density:
Density = mass/volume

Since the density of the object is greater than 2.0 g/ml, the object exerts a downward force on the bottom of the container equal to its weight. Therefore, the force that the object exerts on the bottom of the container is calculated as:
Force = weight of the object = 500 g*m/s^2 = 500 N

Therefore, the force that the object exerts on the bottom of the container is 500 N.