To find the values of v3, v4, and S, we first need to determine the acceleration of the object.
Given that the initial velocity (Vo) is 40 m/s, the time interval t1 is 2 seconds, and the time interval t2 is 5 seconds, we can use the formula for acceleration:
a = (Vf - Vo) / t
where: a = acceleration Vf = final velocity Vo = initial velocity t = time interval
For the first time interval t1 = 2s: a1 = (Vf1 - 40m/s) / 2s
For the second time interval t2 = 5s: a2 = (Vf2 - Vf1) / 3s
Now, we can calculate the final velocity for each time interval:
For the first time interval t1 = 2s: Vf1 = Vo + a1 t1 Vf1 = 40m/s + a1 2s
For the second time interval t2 = 5s: Vf2 = Vf1 + a2 t2 Vf2 = Vf1 + a2 5s
Finally, we can calculate the total distance S traveled during the two time intervals:
S = Vo t1 + 0.5 a1 t1^2 + Vf1 t2 + 0.5 a2 t2^2
With the given values and calculated acceleration, you can now solve for v3, v4, and S.
To find the values of v3, v4, and S, we first need to determine the acceleration of the object.
Given that the initial velocity (Vo) is 40 m/s, the time interval t1 is 2 seconds, and the time interval t2 is 5 seconds, we can use the formula for acceleration:
a = (Vf - Vo) / t
where:
a = acceleration
Vf = final velocity
Vo = initial velocity
t = time interval
For the first time interval t1 = 2s:
a1 = (Vf1 - 40m/s) / 2s
For the second time interval t2 = 5s:
a2 = (Vf2 - Vf1) / 3s
Now, we can calculate the final velocity for each time interval:
For the first time interval t1 = 2s:
Vf1 = Vo + a1 t1
Vf1 = 40m/s + a1 2s
For the second time interval t2 = 5s:
Vf2 = Vf1 + a2 t2
Vf2 = Vf1 + a2 5s
Finally, we can calculate the total distance S traveled during the two time intervals:
S = Vo t1 + 0.5 a1 t1^2 + Vf1 t2 + 0.5 a2 t2^2
With the given values and calculated acceleration, you can now solve for v3, v4, and S.