Решить системы уравнений 1. у=х-2 4х+у=5
2. х=-2у х+у=4
3. у=4х х+2у=3

Предыдущий
вопрос Следующий
вопрос

Substitute the value of y from the first equation into the second equation:

4x + x - 2 = 5
5x - 2 = 5
5x = 7
x = 7/5

Now substitute the value of x back into the first equation to find y:

y = 7/5 - 2
y = 7/5 - 10/5
y = -3/5

Therefore, the solution to the first system of equations is x = 7/5 and y = -3/5.

Substitute the value of x from the first equation into the second equation:

-2y + y = 4
-y = 4
y = -4

Now substitute the value of y back into the first equation to find x:

x = -2(-4)
x = 8

Therefore, the solution to the second system of equations is x = 8 and y = -4.

Substitute the value of y from the first equation into the second equation:

x + 2(4x) = 3
x + 8x = 3
9x = 3
x = 1/3

Now substitute the value of x back into the first equation to find y:

y = 4(1/3)
y = 4/3

Therefore, the solution to the third system of equations is x = 1/3 and y = 4/3.