To solve this equation, we can use the Pythagorean identity: sin^2x + cos^2x = 1. We can rewrite the equation as:
sin^2x - 3(1 - sin^2x) = 0sin^2x - 3 + 3sin^2x = 04sin^2x - 3 = 04sin^2x = 3sin^2x = 3/4sinx = ±√(3/4)sinx = ±√3/2
Therefore, the solutions for x are x = π/3, 2π/3, 4π/3, and 5π/3.
To solve this equation, we can use the Pythagorean identity: sin^2x + cos^2x = 1. We can rewrite the equation as:
sin^2x - 3(1 - sin^2x) = 0
sin^2x - 3 + 3sin^2x = 0
4sin^2x - 3 = 0
4sin^2x = 3
sin^2x = 3/4
sinx = ±√(3/4)
sinx = ±√3/2
Therefore, the solutions for x are x = π/3, 2π/3, 4π/3, and 5π/3.