To prove that lg(4,5-x)=lg4,5-lgx, we need to use the properties of logarithms.
First, let's simplify lg(4,5-x) using the change of base formula for logarithms:
lg(4,5 - x) = lg(5 - x) / lg(4)
Now, let's simplify lg4,5-lgx using the properties of logarithms:
lg(4*5) - lg(x)= lg(20) - lg(x)= lg(20/x)
So, lg(4,5-x) = lg(5 - x) / lg(4) = lg(20/x)
Therefore, lg(4,5-x) is not equal to lg4,5-lgx.
To prove that lg(4,5-x)=lg4,5-lgx, we need to use the properties of logarithms.
First, let's simplify lg(4,5-x) using the change of base formula for logarithms:
lg(4,5 - x) = lg(5 - x) / lg(4)
Now, let's simplify lg4,5-lgx using the properties of logarithms:
lg(4*5) - lg(x)
= lg(20) - lg(x)
= lg(20/x)
So, lg(4,5-x) = lg(5 - x) / lg(4) = lg(20/x)
Therefore, lg(4,5-x) is not equal to lg4,5-lgx.