To solve the equation 2x^2 - 3x - 9 = 0, we can use the quadratic formula:
x = (-(-3) ± √((-3)^2 - 42(-9))) / 2*2x = (3 ± √(9 + 72)) / 4x = (3 ± √81) / 4x = (3 ± 9) / 4
So, the solutions to the equation are:x = (3 + 9) / 4 = 12 / 4 = 3x = (3 - 9) / 4 = -6 / 4 = -1.5
Therefore, the solutions to the equation 2x^2 - 3x - 9 = 0 are x = 3 and x = -1.5.
To solve the equation 2x^2 - 3x - 9 = 0, we can use the quadratic formula:
x = (-(-3) ± √((-3)^2 - 42(-9))) / 2*2
x = (3 ± √(9 + 72)) / 4
x = (3 ± √81) / 4
x = (3 ± 9) / 4
So, the solutions to the equation are:
x = (3 + 9) / 4 = 12 / 4 = 3
x = (3 - 9) / 4 = -6 / 4 = -1.5
Therefore, the solutions to the equation 2x^2 - 3x - 9 = 0 are x = 3 and x = -1.5.