(8x+2ay=1,(5x+4ay=2.

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To solve this system of equations by elimination, we can follow these steps:

Step 1: Multiply the first equation by 5 and the second equation by 8 to make the coefficients of x the same:

5(8x + 2ay) = 5(1)
8(5x + 4ay) = 8(2)

This gives us:

40x + 10ay = 5
40x + 32ay = 16

Step 2: Subtract the first equation from the second equation to eliminate x:

(40x + 32ay) - (40x + 10ay) = 16 - 5
32ay - 10ay = 11
22ay = 11
ay = 11/22
ay = 1/2

Step 3: Substitute the value of ay back into one of the original equations to solve for x. Let's use the first equation:

8x + 2(1/2) = 1
8x + 1 = 1
8x = 0
x = 0

Therefore, the solution to the system of equations is x = 0 and ay = 1/2.