To solve this system of equations by elimination, we can follow these steps:
Step 1: Multiply the first equation by 5 and the second equation by 8 to make the coefficients of x the same:
5(8x + 2ay) = 5(1)8(5x + 4ay) = 8(2)
This gives us:
40x + 10ay = 540x + 32ay = 16
Step 2: Subtract the first equation from the second equation to eliminate x:
(40x + 32ay) - (40x + 10ay) = 16 - 532ay - 10ay = 1122ay = 11ay = 11/22ay = 1/2
Step 3: Substitute the value of ay back into one of the original equations to solve for x. Let's use the first equation:
8x + 2(1/2) = 18x + 1 = 18x = 0x = 0
Therefore, the solution to the system of equations is x = 0 and ay = 1/2.
To solve this system of equations by elimination, we can follow these steps:
Step 1: Multiply the first equation by 5 and the second equation by 8 to make the coefficients of x the same:
5(8x + 2ay) = 5(1)
8(5x + 4ay) = 8(2)
This gives us:
40x + 10ay = 5
40x + 32ay = 16
Step 2: Subtract the first equation from the second equation to eliminate x:
(40x + 32ay) - (40x + 10ay) = 16 - 5
32ay - 10ay = 11
22ay = 11
ay = 11/22
ay = 1/2
Step 3: Substitute the value of ay back into one of the original equations to solve for x. Let's use the first equation:
8x + 2(1/2) = 1
8x + 1 = 1
8x = 0
x = 0
Therefore, the solution to the system of equations is x = 0 and ay = 1/2.