1) |х-3|≥2х+1 2) |2х+3|

Предыдущий
вопрос Следующий
вопрос

1) |x-3| ≥ 2x+1

We can split this absolute value inequality into two inequalities:

1a) (x-3) ≥ 2x+1
x - 3 ≥ 2x + 1
-x ≥ 4
x ≤ -4

1b) -(x-3) ≥ 2x+1

Combining the solutions from (1a) and (1b), we have x ≤ -4 or x ≤ 1.

2) |2x+3|

Since there is no inequality sign provided, we cannot solve for a specific range of x. The absolute value of 2x+3 can be expressed as follows: |2x+3| = 2x+3 if 2x+3 ≥ 0, or |2x+3| = -(2x+3) if 2x+3 < 0.