X+1≥√7x-3 √x+√2x-6>10 √18-2x‹3 √10-√x-5<27

Предыдущий
вопрос Следующий
вопрос

x+1 ≥ √(7x-3
To solve this inequality, first square both sides to get rid of the square root
(x+1)² ≥ 7x-
x² + 2x + 1 ≥ 7x -
x² - 5x + 4 ≥
(x-4)(x-1) ≥
The solution for this inequality is x ≤ 1 or x ≥ 4.

√x + √(2x-6) > 1
To solve this inequality, square both sides to eliminate the square root
(x) + 2√x(2x-6) + (2x-6) > 10
x + 4x√(2x-6) + 2x - 6 > 10
5x + 4x√(2x-6) > 10
4x√(2x-6) > 106 - 5
Squaring both sides we get
16x²(2x-6) > (106 - 5x)
After simplifying and solving the above inequality, we get the range of values for x.

√18 - 2x <
To solve this inequality, we first simplify
√18 - 2x <
√18 < 2x +
18 < (2x + 3)
Solving the above inequality will give the range of values for x.

√10 - √(x-5) < 2
To solve this inequality, we first square both sides to get rid of the square root
√10 - √(x-5) < 2
10 - 2√10√(x-5) + (x-5) < 72
15 - 2√10√(x-5) < 72
2√10√(x-5) > -71
After squaring both sides, we can simplify and solve this inequality to get the range of values for x.