Log_2(x+3)+Log2(x-3)=Log_2 7

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To solve this logarithmic equation, we can first combine the two logarithms on the left side using the product rule of logarithms, which states that log(a) + log(b) = log(a*b):

Log2((x+3)(x-3)) = Log2 7

Next, simplify the expression inside the logarithm by using the difference of squares formula:

Log2(x^2 - 3^2) = Log2 7

Log2(x^2 - 9) = Log2 7

Now, set the expressions inside the logarithm equal to each other:

x^2 - 9 = 7

x^2 = 16

x = ±4

Therefore, the solution to the equation is x = ±4.