To solve this expression, we first need to evaluate each trigonometric function at the given angles:
Now we can substitute these values back into the expression:
2 sin(π/4) - 3 tg(π/6) + ctg(-3π/2) - tg(π)= 2 √2 / 2 - 3 √3 + 0 - 0= √2 - 3√3
Therefore, the final result of the expression 2sin(π/4) - 3tg(π/6) + ctg(-3π/2) - tg(π) is √2 - 3√3.
To solve this expression, we first need to evaluate each trigonometric function at the given angles:
sin(π/4) = √2 / 2tg(π/6) = √3ctg(-3π/2) = - 0 (ctg function is undefined at -3π/2)tg(π) = 0Now we can substitute these values back into the expression:
2 sin(π/4) - 3 tg(π/6) + ctg(-3π/2) - tg(π)
= 2 √2 / 2 - 3 √3 + 0 - 0
= √2 - 3√3
Therefore, the final result of the expression 2sin(π/4) - 3tg(π/6) + ctg(-3π/2) - tg(π) is √2 - 3√3.