а√3 sin330°tg(-60°) = √3 (-1/2) (√3) = -3/2
бarcsin(-√3/2) = -60arccos(1/2) = 60°
Таким образом, arcsin(-√3/2) + arccos(1/2) = -60° + 60° = 0°
а
√3 sin330°tg(-60°) = √3 (-1/2) (√3) = -3/2
б
arcsin(-√3/2) = -60
arccos(1/2) = 60°
Таким образом, arcsin(-√3/2) + arccos(1/2) = -60° + 60° = 0°