To solve the equation Cos(pi/2+x) - sin(pi-x) = 0, we first need to use the trigonometric identity that relates the cosine and sine of complementary angles:

cos(90° + x) = sin(x)

Now we can simplify the equation:

cos(pi/2 + x) - sin(pi - x) = 0
sin(x) - sin(pi - x) = 0
sin(x) - sin(pi)cos(x) + cos(pi)sin(x) = 0
sin(x) - 0 + (-1)sin(x) = 0
sin(x) + sin(x) = 0
2sin(x) = 0

Therefore, the solution to the equation is sin(x) = 0. This occurs when x is an integer multiple of pi:

x = n*pi, where n is an integer.