Решите уравнение:
4х-3/х+1-6х-5/2х+1=1
х2+33/х2-9=8/х+3-х+4/3-х
6/х2+х-х-6/х2-х+10/х2-1=0

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вопрос

1) 4x - 3/(x+1) - 6x - 5/(2x + 1) = 1

4x - 3/(x+1) - 12x - 10/(2x + 1) = 1

4x - 12x - 3/(x+1) - 10/(2x + 1) = 1

-8x - 3/(x+1) - 10/(2x + 1) = 1

-8x - 3(2x + 1)/(x+1)(2x + 1) - 10(x+1)/(x+1)(2x + 1) = 1

-8x - 6x - 3 - 10x - 10 = 2x^2 + 3x + x + 15

-24x - 13 = 2x^2 + 4x + 15

24x + 13 = -2x^2 - 4x - 15

2x^2 + 28x + 28 = 0

x^2 + 14x + 14 = 0

(x + 7)^2 = 0

x = -7

2) x^2 + 33/x^2 - 9 = 8/x + 3 - x + 4/3 - x

x^4 + 33 - 9x^2 = 8x + 3x^2 - 3x^3 + 4x^3 - 3x^4

x^4 + 33 - 9x^2 = -3x^4 + 1x^2 + 8x

4x^4 + 34 = 0

x^4 + 8.5 = 0

3) 6/x^2 + x - x - 6/x^2 - x + 10/x^2 - 1 = 0

6/x^2 - 6/x^2 + 10/x^2 - 1 = 0

10/x^2 - 1 = 0

10 = x^2

x = ±√10