Log4 (4+7x)=log4 (5-х)

Предыдущий
вопрос Следующий
вопрос

To solve this logarithmic equation, we first need to use the property of logarithms that states:

log_a(x) = log_a(y) if and only if x = y.

Given the equation: log4(4+7x) = log4(5-x)

We can rewrite it as: 4+7x = 5-x

Now, solve for x:

7x + x = 5 - 4
8x = 1
x = 1/8

Therefore, the solution to the equation log4(4+7x) = log4(5-x) is x = 1/8.