To solve this equation, we first need to distribute the constants outside the parentheses to the terms inside the parentheses:
8(2y-5) = 16y - 404(3y-7) = 12y - 28
Substitute the results back into the original equation:
16y - 40 - 12y + 28 - 6a = -2y - 12
Now, combine like terms:
16y - 12y - 6a - 40 + 28 = -2y - 124y - 6a - 12 = -2y - 12
Add 2y to both sides:
4y + 2y - 6a - 12 = -126y - 6a - 12 = -12
Add 12 to both sides:
6y - 6a - 12 + 12 = 06y - 6a = 0
Divide by 6:
y - a = 0
Therefore, the solution to the equation is y - a = 0.
To solve this equation, we first need to distribute the constants outside the parentheses to the terms inside the parentheses:
8(2y-5) = 16y - 40
4(3y-7) = 12y - 28
Substitute the results back into the original equation:
16y - 40 - 12y + 28 - 6a = -2y - 12
Now, combine like terms:
16y - 12y - 6a - 40 + 28 = -2y - 12
4y - 6a - 12 = -2y - 12
Add 2y to both sides:
4y + 2y - 6a - 12 = -12
6y - 6a - 12 = -12
Add 12 to both sides:
6y - 6a - 12 + 12 = 0
6y - 6a = 0
Divide by 6:
y - a = 0
Therefore, the solution to the equation is y - a = 0.