To find the points of intersection for these two equations, we can set them equal to each other and solve for the values of x and y.
X^2 = 3x + 4yy^2 = 4x + 3y
Setting X^2 equal to y^2, we have:
3x + 4y = 4x + 3y-x = -yx = y
Substitute x = y into the first equation:
x^2 = 3x + 4xx^2 = 7xx = 0 or x = 7
Since x = y, the points of intersection are (0,0) and (7,7).
To find the points of intersection for these two equations, we can set them equal to each other and solve for the values of x and y.
X^2 = 3x + 4y
y^2 = 4x + 3y
Setting X^2 equal to y^2, we have:
3x + 4y = 4x + 3y
-x = -y
x = y
Substitute x = y into the first equation:
x^2 = 3x + 4x
x^2 = 7x
x = 0 or x = 7
Since x = y, the points of intersection are (0,0) and (7,7).