X^2=3x+4y
y^2= 4x+3y

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вопрос

To find the points of intersection for these two equations, we can set them equal to each other and solve for the values of x and y.

X^2 = 3x + 4y
y^2 = 4x + 3y

Setting X^2 equal to y^2, we have:

3x + 4y = 4x + 3y
-x = -y
x = y

Substitute x = y into the first equation:

x^2 = 3x + 4x
x^2 = 7x
x = 0 or x = 7

Since x = y, the points of intersection are (0,0) and (7,7).