2x-y+xy=44xy-4x+2y=8

Предыдущий
вопрос Следующий
вопрос

To solve this system of equations, we can first isolate one variable in the first equation and substitute it into the second equation to find the values of x and y.

From the first equation: 2x - y + xy = 44
Rearranging this equation to solve for y:
y = 2x + xy - 44

Now, substitute this expression for y into the second equation:
44xy - 4x + 2(2x + xy - 44) = 8
44xy - 4x + 4x + 2xy - 88 = 8
46xy - 88 = 8
46xy = 96
xy = 96 / 46
xy = 48 / 23

Now, substitute xy = 48 / 23 back into the first equation to solve for x and y:
2x - y + 48 / 23 = 44
2x - y = 44 - 48 / 23
2x - y = (44*23 - 48) / 23
2x - y = (1012 - 48) / 23
2x - y = 964 / 23
2x - y = 44

However, this equation is inconsistent with the first equation of the system, suggesting that there may be an error in the initial set of equations provided. Please verify the accuracy of the original equations.