To solve this quadratic equation, we can first rewrite it in standard form:
-x^2 + 20 = x
Bringing all terms to one side, we get:
x^2 + x - 20 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± √(b^2 - 4ac)) / 2a
Here, a = 1, b = 1, and c = -20. Plugging these values into the formula:
x = (-1 ± √(1^2 - 41(-20))) / 2(1)x = (-1 ± √(1 + 80)) / 2x = (-1 ± √81) / 2x = (-1 ± 9) / 2
This gives us two possible values for x:
x = (-1 + 9) / 2 = 8 / 2 = 4x = (-1 - 9) / 2 = -10 / 2 = -5
Therefore, the solutions to the equation are x = 4 and x = -5.
To solve this quadratic equation, we can first rewrite it in standard form:
-x^2 + 20 = x
Bringing all terms to one side, we get:
x^2 + x - 20 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± √(b^2 - 4ac)) / 2a
Here, a = 1, b = 1, and c = -20. Plugging these values into the formula:
x = (-1 ± √(1^2 - 41(-20))) / 2(1)
x = (-1 ± √(1 + 80)) / 2
x = (-1 ± √81) / 2
x = (-1 ± 9) / 2
This gives us two possible values for x:
x = (-1 + 9) / 2 = 8 / 2 = 4
x = (-1 - 9) / 2 = -10 / 2 = -5
Therefore, the solutions to the equation are x = 4 and x = -5.