To solve for t in the equation 4sin²t - 3 = 0, we can first add 3 to both sides:
4sin²t = 3
Next, divide by 4:
sin²t = 3/4
Taking the square root of both sides:
sin t = ±√(3/4)
sin t = ±√3/2
Therefore, t can have two values:
t = sin⁻¹(√3/2) and t = sin⁻¹(-√3/2)
t = π/3 and t = -π/3
So the solutions are t = π/3 and t = -π/3.
To solve for t in the equation 4sin²t - 3 = 0, we can first add 3 to both sides:
4sin²t = 3
Next, divide by 4:
sin²t = 3/4
Taking the square root of both sides:
sin t = ±√(3/4)
sin t = ±√3/2
Therefore, t can have two values:
t = sin⁻¹(√3/2) and t = sin⁻¹(-√3/2)
t = π/3 and t = -π/3
So the solutions are t = π/3 and t = -π/3.