(x^2 + x + 1)^x-3 = 1

Предыдущий
вопрос Следующий
вопрос

To solve this equation, we can first simplify the expression on the left side of the equation:

(x^2 + x + 1)^(x-3) = 1
[(x^2 + x + 1)]^(x-3) = 1
(x^2 + x + 1) = 1

Now, we can solve for x by setting the expression equal to 1:

x^2 + x + 1 = 1
x^2 + x = 0
x(x+1) = 0

This equation can be satisfied if either x = 0 or x = -1. Therefore, the solutions to the original equation are x = 0 or x = -1.