√(x^2 - x) > 2√3x^2 - x > 12x^2 - x - 12 > 0(x - 4)(x + 3) > 0x > 4 or x < -3
√(x + 12) < xx + 12 < x^2x^2 - x - 12 > 0(x - 4)(x + 3) > 0x > 4 or x < -3
√(3x + 1) > √(2 - x)3x + 1 > 2 - x4x > 1x > 1/4
Ответ: x > 4 or x < -3; x > 1/4.
√(x^2 - x) > 2√3
x^2 - x > 12
x^2 - x - 12 > 0
(x - 4)(x + 3) > 0
x > 4 or x < -3
√(x + 12) < x
x + 12 < x^2
x^2 - x - 12 > 0
(x - 4)(x + 3) > 0
x > 4 or x < -3
√(3x + 1) > √(2 - x)
3x + 1 > 2 - x
4x > 1
x > 1/4
Ответ: x > 4 or x < -3; x > 1/4.